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Develop sql to display all customers who belong to country which name end with y.
select * from Customers where Country like ‘%y’;
SELECT * FROM CUSTOMERS WHERE COUNTRY LIKE’%Y’;
select * From Customers Where Country LIKE ‘%Y’
select * from customers where country like ‘%Y’;
select * from customers where country Like ‘y%’;
The % come before Y “%y”;
Select * from customers where country like ‘y%’;
SELECT * from customers where country like “%y”;
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March 13, 2015 at 6:57 pm
select * from Customers
where Country like ‘%y’;
March 16, 2015 at 12:09 am
SELECT * FROM CUSTOMERS WHERE COUNTRY LIKE’%Y’;
March 21, 2015 at 9:02 pm
select * From Customers Where Country LIKE ‘%Y’
March 22, 2015 at 9:15 pm
select * from customers where country like ‘%Y’;
March 25, 2015 at 4:21 pm
select * from customers where country Like ‘y%’;
September 20, 2015 at 12:43 am
The % come before Y
“%y”;
March 26, 2015 at 7:19 pm
Select * from customers where country like ‘y%’;
September 20, 2015 at 12:41 am
SELECT * from customers where country like “%y”;
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Loading Questions
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