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Develop SQL to display all customers which are order by in ascending order on city? Execute and make sure you can display results.
SELECT * FROM Customers order by city; Default order is ascending
To display in descending order SELECT * FROM Customers order by city desc;
SELECT * FROM CUSTOMERS order by city asc;
select * FROM Customers order by City asc
select * from customers order by city ASC;
select * from customers order by city asc;
select *from customers order by city ASC;
Select * from customers order by city ASC;
SELECT * FROM Customers order by City; or SELECT * FROM Customers order by City asc; The default order is ascending.
SELECT *from Customers order by City ASC
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March 15, 2015 at 1:00 am
SELECT * FROM Customers order by city;
Default order is ascending
To display in descending order
SELECT * FROM Customers order by city desc;
March 16, 2015 at 12:03 am
SELECT * FROM CUSTOMERS order by city asc;
March 21, 2015 at 8:48 pm
select * FROM Customers order by City asc
March 22, 2015 at 8:56 pm
select * from customers order by city ASC;
March 22, 2015 at 8:56 pm
select * from customers order by city asc;
March 23, 2015 at 2:41 am
select * from customers order by city ASC;
March 23, 2015 at 6:07 pm
SELECT * FROM CUSTOMERS order by city asc;
March 24, 2015 at 12:02 am
select *from customers order by city ASC;
March 26, 2015 at 7:14 pm
Select * from customers order by city ASC;
March 28, 2015 at 11:05 pm
Select * from customers order by city ASC;
September 19, 2015 at 11:49 pm
SELECT * FROM Customers order by City;
or
SELECT * FROM Customers order by City asc;
The default order is ascending.
October 19, 2015 at 9:17 am
SELECT *from Customers order by City ASC
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If you are facing any issue like can not see video so please login into Google with email what you forwarded to us Google Login or mail to administrator qatraining@infotek-solutions.com
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